๐ŸŒ  ๋ฌธ์ œ

์ด์ง„์ˆ˜๋ฅผ ์˜๋ฏธํ•˜๋Š” ๋‘ ๊ฐœ์˜ ๋ฌธ์ž์—ด bin1๊ณผ bin2๊ฐ€ ๋งค๊ฐœ๋ณ€์ˆ˜๋กœ ์ฃผ์–ด์งˆ ๋•Œ, ๋‘ ์ด์ง„์ˆ˜์˜ ํ•ฉ์„ returnํ•˜๋„๋ก solution ํ•จ์ˆ˜๋ฅผ ์™„์„ฑํ•ด์ฃผ์„ธ์š”.

๐ŸŒ  ์ œํ•œ์‚ฌํ•ญ

  • return ๊ฐ’์€ ์ด์ง„์ˆ˜๋ฅผ ์˜๋ฏธํ•˜๋Š” ๋ฌธ์ž์—ด์ž…๋‹ˆ๋‹ค.
  • 1 ≤ bin1, bin2์˜ ๊ธธ์ด ≤ 10
  • bin1๊ณผ bin2๋Š” 0๊ณผ 1๋กœ๋งŒ ์ด๋ฃจ์–ด์ ธ ์žˆ์Šต๋‹ˆ๋‹ค.
  • bin1๊ณผ bin2๋Š” "0"์„ ์ œ์™ธํ•˜๊ณ  0์œผ๋กœ ์‹œ์ž‘ํ•˜์ง€ ์•Š์Šต๋‹ˆ๋‹ค.

๐ŸŒ  ์ž…์ถœ๋ ฅ ์˜ˆ

bin1 bin2 result
"10" "11" "101"
"1001" "1111" "11000"

๐ŸŒ  ์ž…์ถœ๋ ฅ ์˜ˆ ์„ค๋ช…

์ž…์ถœ๋ ฅ ์˜ˆ #1

  • 10 + 11 = 101 ์ด๋ฏ€๋กœ "101" ์„ returnํ•ฉ๋‹ˆ๋‹ค.

์ž…์ถœ๋ ฅ ์˜ˆ #2

  • 1001 + 1111 = 11000 ์ด๋ฏ€๋กœ "11000"์„ returnํ•ฉ๋‹ˆ๋‹ค.

๐Ÿงž ํ’€์ด

function solution(bin1, bin2) {
    let a = parseInt(bin1, 2);
    let b = parseInt(bin2, 2);
    let c = a + b;
    return c.toString(2);
}

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