๐ŸŒ  ๋ฌธ์ œ

์ฒซ ๋ฒˆ์งธ ๋ถ„์ˆ˜์˜ ๋ถ„์ž์™€ ๋ถ„๋ชจ๋ฅผ ๋œปํ•˜๋Š” numer1, denom1, ๋‘ ๋ฒˆ์งธ ๋ถ„์ˆ˜์˜ ๋ถ„์ž์™€ ๋ถ„๋ชจ๋ฅผ ๋œปํ•˜๋Š” numer2, denom2๊ฐ€ ๋งค๊ฐœ๋ณ€์ˆ˜๋กœ ์ฃผ์–ด์ง‘๋‹ˆ๋‹ค. ๋‘ ๋ถ„์ˆ˜๋ฅผ ๋”ํ•œ ๊ฐ’์„ ๊ธฐ์•ฝ ๋ถ„์ˆ˜๋กœ ๋‚˜ํƒ€๋ƒˆ์„ ๋•Œ ๋ถ„์ž์™€ ๋ถ„๋ชจ๋ฅผ ์ˆœ์„œ๋Œ€๋กœ ๋‹ด์€ ๋ฐฐ์—ด์„ return ํ•˜๋„๋ก solution ํ•จ์ˆ˜๋ฅผ ์™„์„ฑํ•ด๋ณด์„ธ์š”.

๐ŸŒ  ์ œํ•œ์‚ฌํ•ญ

  • 0 <numer1, denom1, numer2, denom2 < 1,000

๐ŸŒ  ์ž…์ถœ๋ ฅ ์˜ˆ


1 2 3 4 [5, 4]
9 2 1 3 [29, 6]

๐ŸŒ  ์ž…์ถœ๋ ฅ ์˜ˆ ์„ค๋ช…

์ž…์ถœ๋ ฅ ์˜ˆ #1

  • 1 / 2 + 3 / 4 = 5 / 4์ž…๋‹ˆ๋‹ค. ๋”ฐ๋ผ์„œ [5, 4]๋ฅผ return ํ•ฉ๋‹ˆ๋‹ค.

์ž…์ถœ๋ ฅ ์˜ˆ #2

  • 9 / 2 + 1 / 3 = 29 / 6์ž…๋‹ˆ๋‹ค. ๋”ฐ๋ผ์„œ [29, 6]์„ return ํ•ฉ๋‹ˆ๋‹ค.

๐Ÿงž ํ’€์ด

function solution(numer1, denom1, numer2, denom2) {
    let a = numer1 * denom2 + numer2 * denom1
    let b = denom1 * denom2
    let maximum = 1
    
    for (let i = 1; i <= a; i++) {
        if(a%i === 0 && b%i === 0) {
            maximum = i
        }
    }
    return [a / maximum, b / maximum]
}

// ์ตœ๋Œ€ ๊ณต์•ฝ์ˆ˜๋ฅผ ๊ตฌํ•˜๊ณ  ํ•ด๋‹น ๊ฐ’์œผ๋กœ ๋ถ„์ž, ๋ถ„๋ชจ๋ฅผ ๋‚˜๋ˆ ์„œ ์ถœ๋ ฅํ•  ๊ฒƒ

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